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	<title>Comments on: Generating Fibonacci: Part II</title>
	<atom:link href="http://samjshah.com/2008/04/24/generating-fibonacci-part-ii/feed/" rel="self" type="application/rss+xml" />
	<link>http://samjshah.com/2008/04/24/generating-fibonacci-part-ii/</link>
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		<title>By: disquisitionesmathematicae</title>
		<link>http://samjshah.com/2008/04/24/generating-fibonacci-part-ii/#comment-984</link>
		<dc:creator><![CDATA[disquisitionesmathematicae]]></dc:creator>
		<pubDate>Wed, 06 May 2009 12:54:41 +0000</pubDate>
		<guid isPermaLink="false">http://samjshah.wordpress.com/?p=140#comment-984</guid>
		<description><![CDATA[Sorry,
$latex g_{n}=2^{n}-1$]]></description>
		<content:encoded><![CDATA[<p>Sorry,<br />
<img src='http://s0.wp.com/latex.php?latex=g_%7Bn%7D%3D2%5E%7Bn%7D-1&amp;bg=ffffff&amp;fg=4e4e4e&amp;s=0' alt='g_{n}=2^{n}-1' title='g_{n}=2^{n}-1' class='latex' /></p>
]]></content:encoded>
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	<item>
		<title>By: disquisitionesmathematicae</title>
		<link>http://samjshah.com/2008/04/24/generating-fibonacci-part-ii/#comment-982</link>
		<dc:creator><![CDATA[disquisitionesmathematicae]]></dc:creator>
		<pubDate>Wed, 06 May 2009 12:53:02 +0000</pubDate>
		<guid isPermaLink="false">http://samjshah.wordpress.com/?p=140#comment-982</guid>
		<description><![CDATA[After reading this post, I got interested in trying this approach to prove the following theorem,

$latex If\  2^{n}-1\ is\ prime,\ then \ n\ is\ prime.$

I tried to exploit the fact that 

$latex g_{n}=2g_{n-1}+1$ where $latex g_{n-1}=2^{n}-1$

The generating function has the form,

$latex p(x)=\frac{x}{(x-1)(2x-1)}$

Any suggestions on how to move further?]]></description>
		<content:encoded><![CDATA[<p>After reading this post, I got interested in trying this approach to prove the following theorem,</p>
<p><img src='http://s0.wp.com/latex.php?latex=If%5C++2%5E%7Bn%7D-1%5C+is%5C+prime%2C%5C+then+%5C+n%5C+is%5C+prime.&amp;bg=ffffff&amp;fg=4e4e4e&amp;s=0' alt='If&#92;  2^{n}-1&#92; is&#92; prime,&#92; then &#92; n&#92; is&#92; prime.' title='If&#92;  2^{n}-1&#92; is&#92; prime,&#92; then &#92; n&#92; is&#92; prime.' class='latex' /></p>
<p>I tried to exploit the fact that </p>
<p><img src='http://s0.wp.com/latex.php?latex=g_%7Bn%7D%3D2g_%7Bn-1%7D%2B1&amp;bg=ffffff&amp;fg=4e4e4e&amp;s=0' alt='g_{n}=2g_{n-1}+1' title='g_{n}=2g_{n-1}+1' class='latex' /> where <img src='http://s0.wp.com/latex.php?latex=g_%7Bn-1%7D%3D2%5E%7Bn%7D-1&amp;bg=ffffff&amp;fg=4e4e4e&amp;s=0' alt='g_{n-1}=2^{n}-1' title='g_{n-1}=2^{n}-1' class='latex' /></p>
<p>The generating function has the form,</p>
<p><img src='http://s0.wp.com/latex.php?latex=p%28x%29%3D%5Cfrac%7Bx%7D%7B%28x-1%29%282x-1%29%7D&amp;bg=ffffff&amp;fg=4e4e4e&amp;s=0' alt='p(x)=&#92;frac{x}{(x-1)(2x-1)}' title='p(x)=&#92;frac{x}{(x-1)(2x-1)}' class='latex' /></p>
<p>Any suggestions on how to move further?</p>
]]></content:encoded>
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	<item>
		<title>By: disquisitionesmathematicae</title>
		<link>http://samjshah.com/2008/04/24/generating-fibonacci-part-ii/#comment-975</link>
		<dc:creator><![CDATA[disquisitionesmathematicae]]></dc:creator>
		<pubDate>Tue, 05 May 2009 14:24:08 +0000</pubDate>
		<guid isPermaLink="false">http://samjshah.wordpress.com/?p=140#comment-975</guid>
		<description><![CDATA[Beautiful !]]></description>
		<content:encoded><![CDATA[<p>Beautiful !</p>
]]></content:encoded>
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