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	<title>Comments on: I missed the deadline</title>
	<atom:link href="http://samjshah.com/2008/05/08/i-missed-the-deadline/feed/" rel="self" type="application/rss+xml" />
	<link>http://samjshah.com/2008/05/08/i-missed-the-deadline/</link>
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		<title>By: Monday Math Madness #5: We have a winner &#187; Fun Math Blog</title>
		<link>http://samjshah.com/2008/05/08/i-missed-the-deadline/#comment-83</link>
		<dc:creator><![CDATA[Monday Math Madness #5: We have a winner &#187; Fun Math Blog]]></dc:creator>
		<pubDate>Sat, 10 May 2008 17:14:53 +0000</pubDate>
		<guid isPermaLink="false">http://samjshah.wordpress.com/?p=169#comment-83</guid>
		<description><![CDATA[[...] missed the deadline but blogged about it, providing a brute force [...]]]></description>
		<content:encoded><![CDATA[<p>[...] missed the deadline but blogged about it, providing a brute force [...]</p>
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		<title>By: samjshah</title>
		<link>http://samjshah.com/2008/05/08/i-missed-the-deadline/#comment-81</link>
		<dc:creator><![CDATA[samjshah]]></dc:creator>
		<pubDate>Thu, 08 May 2008 21:48:06 +0000</pubDate>
		<guid isPermaLink="false">http://samjshah.wordpress.com/?p=169#comment-81</guid>
		<description><![CDATA[Thanks.

Yup... Simpler... I always tend to get caught up in things... I went one extra digit than I needed...]]></description>
		<content:encoded><![CDATA[<p>Thanks.</p>
<p>Yup&#8230; Simpler&#8230; I always tend to get caught up in things&#8230; I went one extra digit than I needed&#8230;</p>
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		<title>By: Johan P</title>
		<link>http://samjshah.com/2008/05/08/i-missed-the-deadline/#comment-80</link>
		<dc:creator><![CDATA[Johan P]]></dc:creator>
		<pubDate>Thu, 08 May 2008 20:30:41 +0000</pubDate>
		<guid isPermaLink="false">http://samjshah.wordpress.com/?p=169#comment-80</guid>
		<description><![CDATA[Just wonder about this:
(a + b)² = a² + 2ab + b² 
Since we are looking for squares with all odd digits we can drop even squares. 
If we say, like you did, that b stands for the one-digit and a for all the rest, there follows that (a+b)² always contains an even digit on the second place. Because:  b² is either 01,  09, 25, 49 or 81. a² is always something of the form x00.2ab is always even.
So the sum of b² and 2ab gives you an even digit in the second place.]]></description>
		<content:encoded><![CDATA[<p>Just wonder about this:<br />
(a + b)² = a² + 2ab + b²<br />
Since we are looking for squares with all odd digits we can drop even squares.<br />
If we say, like you did, that b stands for the one-digit and a for all the rest, there follows that (a+b)² always contains an even digit on the second place. Because:  b² is either 01,  09, 25, 49 or 81. a² is always something of the form x00.2ab is always even.<br />
So the sum of b² and 2ab gives you an even digit in the second place.</p>
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